If 3 sin theta = 2 sin 3 theta and 0

Question

(B) Given $3 \sin 	heta = 2 \sin 3 	heta$. Using the identity $\sin 3 	heta = 3 \sin 	heta - 4 \sin^3 	heta$,we have: $3 \sin 	heta = 2(3 \sin \

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$\frac{\sqrt{3}}{2 \sqrt{2}}$

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(B) Given $3 \sin 	heta = 2 \sin 3 	heta$. Using the identity $\sin 3 	heta = 3 \sin 	heta - 4 \sin^3 	heta$,we have: $3 \sin 	heta = 2(3 \sin 	heta - 4 \sin^3 	heta)$ $3 \sin 	heta = 6 \sin 	heta - 8 \sin^3 	heta$ $8 \sin^3 	heta - 3 \sin 	heta = 0$ $\sin 	heta (8 \sin^2 	heta - 3) = 0$ This implies $\sin 	heta = 0$ or $\sin^2 	heta = \frac{3}{8}$. Since $0 Therefore,$\sin 	heta = \sqrt{\frac{3}{8}} = \frac{\sqrt{3}}{2 \sqrt{2}}$.

If $3 \sin \theta = 2 \sin 3 \theta$ and $0 < \theta < \pi$,then $\sin \theta =$

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