જો omega એ એકમનું ઘનમૂળ હોય,તો left| begin{ar | vedclass

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(D) ધારો કે $\Delta = \left| \begin{array}{ccc} x + 1 & \omega & \omega^2 \ \omega & x + \omega^2 & 1 \ \omega^2 & 1 & x + \omega \end{array} ight

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$x^3$

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(D) ધારો કે $\Delta = \left| \begin{array}{ccc} x + 1 & \omega & \omega^2 \ \omega & x + \omega^2 & 1 \ \omega^2 & 1 & x + \omega \end{array} ight|$.સ્તંભ પ્રક્રિયા $C_1 	o C_1 + C_2 + C_3$ લાગુ પાડતા:$\Delta = \left| \begin{array}{ccc} x + 1 + \omega + \omega^2 & \omega & \omega^2 \ x + 1 + \omega + \omega^2 & x + \omega^2 & 1 \ x + 1 + \omega + \omega^2 & 1 & x + \omega \end{array} ight|$.કારણ કે $1 + \omega + \omega^2 = 0$,પ્રથમ સ્તંભ $x$ બને છે:$\Delta = x \left| \begin{array}{ccc} 1 & \omega & \omega^2 \ 1 & x + \omega^2 & 1 \ 1 & 1 & x + \omega \end{array} ight|$.પ્રથમ સ્તંભની સાપેક્ષ વિસ્તરણ કરતા:$\Delta = x [ 1((x + \omega^2)(x + \omega) - 1) - 1(\omega(x + \omega) - \omega^2) + 1(\omega - \omega^2(x + \omega^2)) ]$.પદોનું સાદું રૂપ આપતા:$= x [ (x^2 + \omega x + \omega^2 x + \omega^3 - 1) - (\omega x + \omega^2 - \omega^2) + (\omega - \omega^2 x - \omega^4) ]$.$\omega^3 = 1$ અને $\omega^4 = \omega$ નો ઉપયોગ કરતા:$= x [ x^2 + \omega x + \omega^2 x + 1 - 1 - \omega x + \omega - \omega^2 x - \omega ] = x [ x^2 ] = x^3$.

જો $\omega$ એ એકમનું ઘનમૂળ હોય,તો $\left| \begin{array}{ccc} x + 1 & \omega & \omega^2 \\ \omega & x + \omega^2 & 1 \\ \omega^2 & 1 & x + \omega \end{array} \right| = $

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$\left| {\begin{array}{ccc} 19 & 17 & 15 \\ 9 & 8 & 7 \\ 1 & 1 & 1 \end{array}} \right| = $

જો $\left| \begin{array}{ccc} 1 & k & 3 \\ 3 & k & -2 \\ 2 & 3 & -1 \end{array} \right| = 0$ હોય,તો $k$ ની કિંમત શોધો.

સાબિત કરો કે $\left|\begin{array}{ccc}b+c & a & a \\ b & c+a & b \\ c & c & a+b\end{array}\right|=4abc$

જો $a, b, c$ ભિન્ન હોય અને $\left| \begin{array}{ccc} a & a^2 & a^3 - 1 \\ b & b^2 & b^3 - 1 \\ c & c^2 & c^3 - 1 \end{array} \right| = 0$ હોય,તો

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