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(C) Given $A = \begin{bmatrix} 1 & 2 & 3 \ 1 & 4 & 9 \ 1 & 8 & 27 \end{bmatrix}$.First,we calculate the determinant of $A$,denoted by $|A|$.$|A| = 1

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$144$

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(C) Given $A = \begin{bmatrix} 1 & 2 & 3 \ 1 & 4 & 9 \ 1 & 8 & 27 \end{bmatrix}$.First,we calculate the determinant of $A$,denoted by $|A|$.$|A| = 1(4 	imes 27 - 9 	imes 8) - 2(1 	imes 27 - 9 	imes 1) + 3(1 	imes 8 - 4 	imes 1)$$|A| = 1(108 - 72) - 2(27 - 9) + 3(8 - 4)$$|A| = 1(36) - 2(18) + 3(4)$$|A| = 36 - 36 + 12 = 12$.We know that for a square matrix $A$ of order $n$,$|adj\, A| = |A|^{n-1}$.Here,the order of matrix $A$ is $n = 3$.Therefore,$|adj\, A| = |A|^{3-1} = |A|^2$.$|adj\, A| = (12)^2 = 144$.

If $A = \begin{bmatrix} 1 & 2 & 3 \\ 1 & 4 & 9 \\ 1 & 8 & 27 \end{bmatrix}$,then the value of $|adj\, A|$ is

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