If sin theta = -frac{1}{sqrt{2}} and tan thet | vedclass

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(C) Given that $\sin 	heta = -\frac{1}{\sqrt{2}}$ and $	an 	heta = 1$.In the Cartesian coordinate system,the signs of trigonometric functions in di

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(C) Given that $\sin 	heta = -\frac{1}{\sqrt{2}}$ and $	an 	heta = 1$.In the Cartesian coordinate system,the signs of trigonometric functions in different quadrants are as follows:- $I$ quadrant: All positive- $II$ quadrant: $\sin$ is positive- $III$ quadrant: $	an$ is positive- $IV$ quadrant: $\cos$ is positiveSince $\sin 	heta$ is negative and $	an 	heta$ is positive,$	heta$ must lie in the $III$ quadrant,where both $\sin$ and $\cos$ are negative,making $	an 	heta = \frac{\sin 	heta}{\cos 	heta}$ positive.

If $\sin \theta = -\frac{1}{\sqrt{2}}$ and $\tan \theta = 1$,then $\theta$ lies in which quadrant?

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