If tan theta = frac{x sin phi}{1 - x cos phi} | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given $	an 	heta = \frac{x \sin \phi}{1 - x \cos \phi}$.Rearranging,we get $	an 	heta - x 	an 	heta \cos \phi = x \sin \phi$.$	an 	heta =

Vedclass · Accepted Answer

$\frac{\sin 	heta}{\sin \phi}$

Vedclass · Answer

(B) Given $	an 	heta = \frac{x \sin \phi}{1 - x \cos \phi}$.Rearranging,we get $	an 	heta - x 	an 	heta \cos \phi = x \sin \phi$.$	an 	heta = x(\sin \phi + \cos \phi 	an 	heta) = x \left( \frac{\sin \phi \cos 	heta + \cos \phi \sin 	heta}{\cos 	heta} ight) = x \frac{\sin(\phi + 	heta)}{\cos 	heta}$.Thus,$x = \frac{	an 	heta \cos 	heta}{\sin(	heta + \phi)} = \frac{\sin 	heta}{\sin(	heta + \phi)}$.Similarly,from $	an \phi = \frac{y \sin 	heta}{1 - y \cos 	heta}$,we get $y = \frac{\sin \phi}{\sin(	heta + \phi)}$.Therefore,$\frac{x}{y} = \frac{\sin 	heta / \sin(	heta + \phi)}{\sin \phi / \sin(	heta + \phi)} = \frac{\sin 	heta}{\sin \phi}$.

If $\tan \theta = \frac{x \sin \phi}{1 - x \cos \phi}$ and $\tan \phi = \frac{y \sin \theta}{1 - y \cos \theta}$,then $\frac{x}{y} = $

Similar Questions

If $x = \sec \phi - \tan \phi$ and $y = \csc \phi + \cot \phi$,then:

If $\cos \alpha = \operatorname{sech} \beta$,then $\beta =$

If $\sin A+\sin B=\sqrt{3}(\cos B-\cos A)$,then $\sin 3A+\sin 3B$ is equal to

$\sin \frac{\pi}{16} \sin \frac{3 \pi}{16} \sin \frac{5 \pi}{16} \sin \frac{7 \pi}{16}$ is equal to

$\sqrt{3} \operatorname{cosec} 20^{\circ} - \sec 20^{\circ}$ is equal to

Vedclass Test Series

Exam Paper Generator

Online Exam Module