જો $\tan \theta = \frac{a}{b}$ હોય,તો $\frac{\sin \theta}{\cos^8 \theta} + \frac{\cos \theta}{\sin^8 \theta} = $

• A
  $\pm \frac{({a^2} + {b^2})^4}{\sqrt{a^2 + b^2}} \left( \frac{a}{b^8} + \frac{b}{a^8} \right)$
• B
  $\pm \frac{({a^2} + {b^2})^4}{\sqrt{a^2 + b^2}} \left( \frac{a}{b^8} - \frac{b}{a^8} \right)$
• C
  $\pm \frac{({a^2} - {b^2})^4}{\sqrt{a^2 + b^2}} \left( \frac{a}{b^8} + \frac{b}{a^8} \right)$
• D
  $\pm \frac{({a^2} - {b^2})^4}{\sqrt{a^2 - b^2}} \left( \frac{a}{b^8} - \frac{b}{a^8} \right)$