If A = begin{bmatrix} 5 & -2 4 & 3 end{bmatr | vedclass

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(C) We know that for any square matrix $A$ of order $n$,the property $A(\operatorname{adj} A) = |A| I$ holds,where $I$ is the identity matrix of order

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$23 I$

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(C) We know that for any square matrix $A$ of order $n$,the property $A(\operatorname{adj} A) = |A| I$ holds,where $I$ is the identity matrix of order $n$.Given $A = \begin{bmatrix} 5 & -2 \ 4 & 3 \end{bmatrix}$.The determinant of $A$ is $|A| = (5 	imes 3) - (-2 	imes 4) = 15 - (-8) = 15 + 8 = 23$.Since the order of matrix $A$ is $2 	imes 2$,we have $I = \begin{bmatrix} 1 & 0 \ 0 & 1 \end{bmatrix}$.Therefore,$A(\operatorname{adj} A) = |A| I = 23 \begin{bmatrix} 1 & 0 \ 0 & 1 \end{bmatrix} = 23 I$.

If $A = \begin{bmatrix} 5 & -2 \\ 4 & 3 \end{bmatrix}$,then $A(\operatorname{adj} A) = $ . . . . . . .

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