If 22 g of benzene (C_6H_6) is dissolved in | vedclass

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Question

(C) The mass percentage of a solute is calculated using the formula: $	ext{Mass percentage} = \frac{	ext{Mass of solute}}{	ext{Mass of solute} +

Vedclass · Accepted Answer

$15.28$

Vedclass · Answer

(C) The mass percentage of a solute is calculated using the formula: $	ext{Mass percentage} = \frac{	ext{Mass of solute}}{	ext{Mass of solute} + 	ext{Mass of solvent}} 	imes 100$. Given: $	ext{Mass of benzene (solute)} = 22 \ g$. $	ext{Mass of carbon tetrachloride (solvent)} = 122 \ g$. $	ext{Total mass of solution} = 22 \ g + 122 \ g = 144 \ g$. $	ext{Mass percentage of benzene} = \frac{22}{144} 	imes 100 = 15.277 \% \approx 15.28 \%$. Therefore,the correct option is $C$.

If $22 \ g$ of benzene $(C_6H_6)$ is dissolved in $122 \ g$ of carbon tetrachloride $(CCl_4)$,calculate the mass percentage of benzene. (in $\%$)

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