If n = (2020)!,then the value of frac{1}{log | vedclass

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(B) Using the property $\frac{1}{\log _{a} b} = \log _{b} a$,we can rewrite the expression as: $\log _{n} 2 + \log _{n} 3 + \log _{n} 4 + \ldots + \lo

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$1$

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(B) Using the property $\frac{1}{\log _{a} b} = \log _{b} a$,we can rewrite the expression as: $\log _{n} 2 + \log _{n} 3 + \log _{n} 4 + \ldots + \log _{n} 2020$ Using the property $\log _{b} x + \log _{b} y = \log _{b} (xy)$,we get: $\log _{n} (2 	imes 3 	imes 4 	imes \ldots 	imes 2020)$ Since $n = (2020)!$,the expression becomes: $\log _{n} (n) = 1$

If $n = (2020)!$,then the value of $\frac{1}{\log _{2} n} + \frac{1}{\log _{3} n} + \frac{1}{\log _{4} n} + \ldots + \frac{1}{\log _{2020} n}$ is equal to:

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