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(B) Given the equation $\begin{bmatrix} 2 & 1 \ 3 & 2 \end{bmatrix} A = I$,where $I$ is the identity matrix. Let $B = \begin{bmatrix} 2 & 1 \ 3 & 2

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$\begin{bmatrix} 2 & -1 \ -3 & 2 \end{bmatrix}$

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(B) Given the equation $\begin{bmatrix} 2 & 1 \ 3 & 2 \end{bmatrix} A = I$,where $I$ is the identity matrix. Let $B = \begin{bmatrix} 2 & 1 \ 3 & 2 \end{bmatrix}$. Then $BA = I$,which implies $A = B^{-1}$. The inverse of a $2 	imes 2$ matrix $\begin{bmatrix} a & b \ c & d \end{bmatrix}$ is given by $\frac{1}{ad-bc} \begin{bmatrix} d & -b \ -c & a \end{bmatrix}$. Here,$ad-bc = (2)(2) - (1)(3) = 4 - 3 = 1$. Thus,$B^{-1} = \frac{1}{1} \begin{bmatrix} 2 & -1 \ -3 & 2 \end{bmatrix} = \begin{bmatrix} 2 & -1 \ -3 & 2 \end{bmatrix}$. Therefore,$A = \begin{bmatrix} 2 & -1 \ -3 & 2 \end{bmatrix}$.

If $\begin{bmatrix} 2 & 1 \\ 3 & 2 \end{bmatrix} A = \begin{bmatrix} 1 & 0 \\ 0 & 1 \end{bmatrix}$,then the matrix $A$ is

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