If A and B are two events of a sample space S | vedclass

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(D) Given that $P(A)=0.2$,$P(B)=0.6$ and $P(A \mid B)=0.5$. We know that the conditional probability is defined as $P(A \mid B) = \frac{P(A \cap B)}{P

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$ \frac{1}{2} $

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(D) Given that $P(A)=0.2$,$P(B)=0.6$ and $P(A \mid B)=0.5$. We know that the conditional probability is defined as $P(A \mid B) = \frac{P(A \cap B)}{P(B)}$. Substituting the given values: $0.5 = \frac{P(A \cap B)}{0.6}$. Therefore,$P(A \cap B) = 0.5 	imes 0.6 = 0.3$. We need to find $P(A^{\prime} \mid B)$. Using the property of conditional probability,$P(A^{\prime} \mid B) = 1 - P(A \mid B)$. Thus,$P(A^{\prime} \mid B) = 1 - 0.5 = 0.5 = \frac{1}{2}$.

If $A$ and $B$ are two events of a sample space $S$ such that $P(A)=0.2$,$P(B)=0.6$ and $P(A \mid B)=0.5$,then $P(A^{\prime} \mid B) = $

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