If $\frac{2 x^3+x^2-5}{x^4-25}=\frac{A x+B}{x^2-5}+\frac{C x+1}{x^2+5}$,then $(A, B, C)$ equals to

  • A
    $(1, 1, 1)$
  • B
    $(1, 1, 0)$
  • C
    $(1, 0, 1)$
  • D
    $(1, 2, 1)$

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