If $x$ is the number of ways in which six women and six men can be arranged to sit in a row such that no two women are together and if $y$ is the number of ways they are seated around a table in the same manner,then $x: y=$ (in $: 1$)

  • A
    $12$
  • B
    $42$
  • C
    $16$
  • D
    $6$

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