If 200 text{ MeV} of energy is released in th | vedclass

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(A) The energy released per fission of one nucleus is $E_1 = 200 	ext{ MeV}$.First,convert this energy into Joules $(J)$:$E_1 = 200 	imes 10^6 	ext

Vedclass · Accepted Answer

$3.125 	imes 10^{13}$

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(A) The energy released per fission of one nucleus is $E_1 = 200 	ext{ MeV}$.First,convert this energy into Joules $(J)$:$E_1 = 200 	imes 10^6 	ext{ eV} = 200 	imes 10^6 	imes 1.6 	imes 10^{-19} 	ext{ J} = 3.2 	imes 10^{-11} 	ext{ J}$.We need to find the number of nuclei $N$ required to release a total energy $E_{	ext{total}} = 1000 	ext{ J}$.The formula is $N = \frac{E_{	ext{total}}}{E_1}$.Substituting the values:$N = \frac{1000}{3.2 	imes 10^{-11}} = \frac{1000}{3.2} 	imes 10^{11} = 312.5 	imes 10^{11} = 3.125 	imes 10^{13}$.Therefore,the number of nuclei required is $3.125 	imes 10^{13}$.

If $200 \text{ MeV}$ of energy is released in the fission of one nucleus of ${ }_{92}^{235} \text{U}$,then the number of nuclei that must undergo fission to release an energy of $1000 \text{ J}$ is

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