If $S_{n} = 1^3 + 2^3 + \ldots + n^3$ and $T_{n} = 1 + 2 + \ldots + n$,then
- A$S_{n} = T_{n^3}$
- B$S_{n} = T_{n}^3$
- C$S_{n} = T_{n^2}$
- D$S_{n} = T_{n}^2$
Explore More
Similar Questions
The polar equation $\cos \theta + 7 \sin \theta = \frac{1}{r}$ represents a
The foot of the perpendicular from $(0,2,3)$ to the line $\frac{x+3}{5}=\frac{y-1}{2}=\frac{z+4}{3}$ is
The abundance of a species population within its habitat is called
Which of the following pairs of $2,3$-butanediol are enantiomeric?
If $\omega$ is a complex cube root of unity,then $225+(3 \omega+8 \omega^2)^2+(3 \omega^2+8 \omega)^2$ is equal to:
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo