જો $A = \{x \in [0, 2\pi] : \tan x - \tan^2 x > 0\}$ અને $B = \{x \in [0, 2\pi] : |\sin x| < \frac{1}{2}\}$,હોય,તો $A \cap B = $

• A
  $\left(0, \frac{\pi}{6}\right) \cup \left(\pi, \frac{7\pi}{6}\right)$
• B
  $\left(0, \frac{\pi}{4}\right) \cup \left(\pi, \frac{7\pi}{6}\right)$
• C
  $\left(0, \frac{\pi}{6}\right) \cup \left(\frac{5\pi}{6}, \frac{7\pi}{6}\right)$
• D
  $\left(\frac{\pi}{6}, \frac{7\pi}{6}\right)$