If PS is the median of the triangle with vert | vedclass

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(D) Since $S$ is the midpoint of $QR$,its coordinates are $S = \left(\frac{6+7}{2}, \frac{-1+3}{2}\right) = \left(\frac{13}{2}, 1\right)$.The slope of

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$2x+9y+7=0$

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(D) Since $S$ is the midpoint of $QR$,its coordinates are $S = \left(\frac{6+7}{2}, \frac{-1+3}{2}\right) = \left(\frac{13}{2}, 1\right)$.The slope of the median $PS$ is $m = \frac{1-2}{\frac{13}{2}-2} = \frac{-1}{\frac{9}{2}} = -\frac{2}{9}$.The line parallel to $PS$ has the same slope $m = -\frac{2}{9}$.The equation of the line passing through $(1, -1)$ with slope $m = -\frac{2}{9}$ is given by $y - y_1 = m(x - x_1)$.$y - (-1) = -\frac{2}{9}(x - 1)$$9(y + 1) = -2(x - 1)$$9y + 9 = -2x + 2$$2x + 9y + 7 = 0$.

If $PS$ is the median of the triangle with vertices $P(2,2)$,$Q(6,-1)$ and $R(7,3)$,then the equation of the line passing through $(1,-1)$ and parallel to $PS$ is

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