If $(a, b)$ is the midpoint of the chord $2x - y + 3 = 0$ of the circle $x^2 + y^2 + 6x - 4y + 4 = 0$,then $2a + 3b =$

  • A
    -$1$
  • B
    $0$
  • C
    $1$
  • D
    $3$

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