If x+5=0 is the directrix and (-3,0) is the v | vedclass

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(A) The directrix is $x = -5$ and the vertex is $V(-3, 0)$.Since the directrix is a vertical line,the axis of the parabola is horizontal (the $x$-axis

Vedclass · Accepted Answer

$y^2=8(x+3)$

Vedclass · Answer

(A) The directrix is $x = -5$ and the vertex is $V(-3, 0)$.Since the directrix is a vertical line,the axis of the parabola is horizontal (the $x$-axis).The distance from the vertex to the directrix is $a = |-3 - (-5)| = 2$.Since the vertex is to the right of the directrix,the parabola opens to the right.The standard form of a parabola opening to the right with vertex $(h, k)$ is $(y-k)^2 = 4a(x-h)$.Substituting $h = -3$,$k = 0$,and $a = 2$,we get:$(y-0)^2 = 4(2)(x - (-3))$$y^2 = 8(x+3)$

If $x+5=0$ is the directrix and $(-3,0)$ is the vertex of a parabola,then the equation of this parabola is . . . . . .

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