Class 11MathematicsTrigonometrical EquationsRelation between sides and angles, Solutions of triangles
EasyIf $a=2, b=3, c=4$ in a triangle $ABC$,then $\cos C=$
- A$\frac{1}{4}$
- B$\frac{-1}{4}$
- C$\frac{1}{2}$
- D$\frac{-1}{2}$
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If in a $\triangle ABC$,$\frac{1}{a+c} + \frac{1}{b+c} = \frac{3}{a+b+c}$,then $\angle C$ is equal to (in $^{\circ}$)
DifficultAP EAMCET 2013
View SolutionIn a triangle $ABC$ with usual notations,if $\angle A = 30^{\circ}$,then the value of $\left(1+\frac{a}{c}+\frac{b}{c}\right)\left(1+\frac{c}{b}-\frac{a}{b}\right)=$
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