If $x=3 \cos t$ and $y=4 \sin t$,then $\frac{d^2 y}{d x^2}$ at the point $(x_0, y_0)=(\frac{3}{2} \sqrt{2}, 2 \sqrt{2})$ is

  • A
    $\frac{4 \sqrt{2}}{9}$
  • B
    $-\frac{4 \sqrt{2}}{9}$
  • C
    $\frac{8 \sqrt{2}}{9}$
  • D
    $-\frac{8 \sqrt{2}}{9}$

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