If $\frac{1}{(3-5 x)(2+3 x)}=\frac{A}{3-5 x}+\frac{B}{2+3 x}$,then $A+B$ is equal to

  • A
    $\frac{7}{19}$
  • B
    $\frac{8}{19}$
  • C
    $\frac{9}{19}$
  • D
    $\frac{10}{19}$

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