If bar{a} = 2bar{i} - 3bar{j} + 5bar{k} and b | vedclass

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(A) Given vectors are $\bar{a} = 2\bar{i} - 3\bar{j} + 5\bar{k}$ and $\bar{b} = -\bar{i} + 3\bar{j} + 3\bar{k}$.First,calculate the vector $\bar{c} =

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$12\bar{i} - 24\bar{j} + 8\bar{k}$

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(A) Given vectors are $\bar{a} = 2\bar{i} - 3\bar{j} + 5\bar{k}$ and $\bar{b} = -\bar{i} + 3\bar{j} + 3\bar{k}$.First,calculate the vector $\bar{c} = \bar{a} - \bar{b}$:$\bar{c} = (2 - (-1))\bar{i} + (-3 - 3)\bar{j} + (5 - 3)\bar{k} = 3\bar{i} - 6\bar{j} + 2\bar{k}$.Next,find the magnitude of $\bar{c}$:$|\bar{c}| = \sqrt{3^2 + (-6)^2 + 2^2} = \sqrt{9 + 36 + 4} = \sqrt{49} = 7$.The unit vector in the direction of $\bar{c}$ is $\hat{c} = \frac{\bar{c}}{|\bar{c}|} = \frac{3\bar{i} - 6\bar{j} + 2\bar{k}}{7}$.The required vector of magnitude $28$ units is $28 	imes \hat{c}$:$28 	imes \left( \frac{3\bar{i} - 6\bar{j} + 2\bar{k}}{7} ight) = 4(3\bar{i} - 6\bar{j} + 2\bar{k}) = 12\bar{i} - 24\bar{j} + 8\bar{k}$.

If $\bar{a} = 2\bar{i} - 3\bar{j} + 5\bar{k}$ and $\bar{b} = -\bar{i} + 3\bar{j} + 3\bar{k}$ are two vectors,then the vector of magnitude $28$ units in the direction of the vector $\bar{a} - \bar{b}$ is

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