If $7 \hat{i}-4 \hat{j}+5 \hat{k}$ is the position vector of the vertex $A$ of a tetrahedron $ABCD$ and $-\hat{i}+4 \hat{j}-3 \hat{k}$ is the position vector of the centroid of the triangle $BCD$,then the position vector of the centroid of the tetrahedron $ABCD$ is

  • A
    $-\hat{i}+4 \hat{j}-3 \hat{k}$
  • B
    $-\frac{1}{2} \hat{i}+4 \hat{j}-3 \hat{k}$
  • C
    $\hat{i}+2 \hat{j}-\hat{k}$
  • D
    $-\hat{i}-2 \hat{j}+\hat{k}$

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