If $A=(0,4,-3)$,$B=(5,0,12)$,and $C=(7,24,0)$,then $\angle BAC=$

  • A
    $60^{\circ}$
  • B
    $\cos^{-1}\left(\frac{16}{\sqrt{13}}\right)$
  • C
    $\cos^{-1}\left(\frac{13}{38}\right)$
  • D
    $90^{\circ}$

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