If P=(0,1,2), Q=(4,-2,1) and O=(0,0,0),then a | vedclass

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(D) Given vectors are $\vec{OP} = 0\hat{i} + 1\hat{j} + 2\hat{k}$ and $\vec{OQ} = 4\hat{i} - 2\hat{j} + 1\hat{k}$.To find the angle $	heta$ between $

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$\frac{\pi}{2}$

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(D) Given vectors are $\vec{OP} = 0\hat{i} + 1\hat{j} + 2\hat{k}$ and $\vec{OQ} = 4\hat{i} - 2\hat{j} + 1\hat{k}$.To find the angle $	heta$ between $\vec{OP}$ and $\vec{OQ}$,we use the dot product formula: $\cos 	heta = \frac{\vec{OP} \cdot \vec{OQ}}{|\vec{OP}| |\vec{OQ}|}$.First,calculate the dot product: $\vec{OP} \cdot \vec{OQ} = (0)(4) + (1)(-2) + (2)(1) = 0 - 2 + 2 = 0$.Since the dot product is $0$,the vectors are perpendicular.Therefore,$\cos 	heta = 0$,which implies $	heta = \frac{\pi}{2}$.

If $P=(0,1,2), Q=(4,-2,1)$ and $O=(0,0,0)$,then $\angle POQ=$

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