If $A(4,7,8)$,$B(2,3,4)$,and $C(2,5,7)$ are the position vectors of the vertices of a triangle $ABC$ and if the internal bisector of $\angle A$ meets $BC$ at $D$,then $AD=$

  • A
    $\frac{3}{2} \sqrt{34}$
  • B
    $\frac{2}{3} \sqrt{34}$
  • C
    $\frac{1}{2} \sqrt{34}$
  • D
    $\frac{1}{6} \sqrt{34}$

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