If CO_2 gas having a partial pressure of 1.67 | vedclass

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Question

(C) According to Henry's law: $p = K_H 	imes \chi$Given: $p = 1.67 \ bar$,$K_H = 1.67 \ kbar = 1670 \ bar$.Calculating mole fraction $\chi$ of $CO_2$

Vedclass · Accepted Answer

$2.44$

Vedclass · Answer

(C) According to Henry's law: $p = K_H 	imes \chi$Given: $p = 1.67 \ bar$,$K_H = 1.67 \ kbar = 1670 \ bar$.Calculating mole fraction $\chi$ of $CO_2$: $\chi = \frac{p}{K_H} = \frac{1.67}{1670} = 0.001$.Since the amount of $CO_2$ is very small,$\chi = \frac{n_{CO_2}}{n_{H_2O}} \approx 0.001$.Number of moles of water in $1 \ L$ is $n_{H_2O} = \frac{1000 \ g}{18 \ g \ mol^{-1}} = 55.55 \ mol$.Therefore,$n_{CO_2} = 0.001 	imes 55.55 = 0.05555 \ mol$.Mass of $CO_2 = n_{CO_2} 	imes 	ext{Molar mass of } CO_2 = 0.05555 \ mol 	imes 44 \ g \ mol^{-1} \approx 2.44 \ g$.Thus,the amount of $CO_2$ dissolved is $2.44 \ g \ L^{-1}$.

Gas	$K_{H} \ (kbar)$
$\alpha$	$50$
$\beta$	$2$
$\gamma$	$2 \times 10^{-5}$
$\delta$	$0.5$

If $CO_2$ gas having a partial pressure of $1.67 \ bar$ is bubbled through $1 \ L$ water at $298 \ K$,the amount of $CO_2$ dissolved in water in $g \ L^{-1}$ is approximately. (Henry's law constant of $CO_2$ is $1.67 \ kbar$ at $298 \ K$)

Similar Questions

The partial pressure of ethane over a solution containing $7.14 \times 10^{-3} \ g$ of ethane is $1 \ bar$. If the solution contains $5 \times 10^{-2} \ g$ of ethane,then what shall be the partial pressure of the gas (in $bar$)? (At equal temperature)

State Henry's law and mention some important applications.

Assertion : The molecules of the dissolved gas present in a liquid gain kinetic energy as temperature is raised.
Reason : Gases tend to be more soluble in liquids as the temperature is raised.

Calculate the solubility of gas in water at $1.2 \text{ atm}$ and $25^{\circ} C$ if Henry's law constant is $0.45 \text{ mol dm}^{-3} \text{ atm}^{-1}$ at $25^{\circ} C$.

Henry's constant (in $kbar$) for four gases $\alpha, \beta, \gamma$ and $\delta$ in water at $298 \ K$ is given below:

Gas $K_{H} \ (kbar)$

$\alpha$ $50$

$\beta$ $2$

$\gamma$ $2 \times 10^{-5}$

$\delta$ $0.5$

(Density of water $= 10^{3} \ kg \ m^{-3}$ at $298 \ K$). This table implies that:

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