If $\alpha$ and $\beta$ are the roots of the quadratic equation $3x^2 - 16x + 5 = 0$,then $\tan^{-1} \alpha + \tan^{-1} \beta - \tan^{-1}\left(\frac{\alpha + \beta}{1 - \alpha \beta}\right) = $

  • A
    $0$
  • B
    $\pi$
  • C
    $\frac{\pi}{2}$
  • D
    $-\pi$

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