If x is numerically so small that x^2 and hig | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given expression: $E = (1 + \frac{2x}{3})^{3/2} \cdot (32 + 5x)^{-1/5}$ Using the binomial approximation $(1+u)^n \approx 1+nu$ for small $u$: $E

Vedclass · Accepted Answer

$\frac{32+31x}{64}$

Vedclass · Answer

(A) Given expression: $E = (1 + \frac{2x}{3})^{3/2} \cdot (32 + 5x)^{-1/5}$ Using the binomial approximation $(1+u)^n \approx 1+nu$ for small $u$: $E \approx (1 + \frac{3}{2} \cdot \frac{2x}{3}) \cdot (32)^{-1/5} (1 + \frac{5x}{32})^{-1/5}$ $E \approx (1 + x) \cdot \frac{1}{2} \cdot (1 - \frac{1}{5} \cdot \frac{5x}{32})$ $E \approx \frac{1}{2} (1 + x) (1 - \frac{x}{32})$ Neglecting $x^2$ terms: $E \approx \frac{1}{2} (1 + x - \frac{x}{32}) = \frac{1}{2} (1 + \frac{31x}{32}) = \frac{32 + 31x}{64}$

If $x$ is numerically so small that $x^2$ and higher powers of $x$ can be neglected, then $\left(1+\frac{2x}{3}\right)^{3/2} \cdot (32+5x)^{-1/5}$ is approximately equal to

Similar Questions

The sum of the coefficients of $x^{-3/2}$ and $x^3$ in the expansion of $\sqrt{3+x} + \sqrt{5+x}$ when $3 < x < 5$ is

The binomial expansion $(7+3x)^{-2/5}$ is valid for all $x$ in the interval $\left(\frac{-7}{3}, \frac{7}{3}\right)$. If the $4^{th}$ term of its expansion is $kx^3$,then the value of $(7^{12/5}k)$ is:

$\frac{1}{4}-\frac{5}{4 \cdot 8}+\frac{5 \cdot 9}{4 \cdot 8 \cdot 12}-\ldots=$

If $x=\frac{2}{5}+\frac{1 \cdot 3}{2 !}\left(\frac{2}{5}\right)^2+\frac{1 \cdot 3 \cdot 5}{3 !}\left(\frac{2}{5}\right)^3+\ldots$,then $x+\frac{1}{x}=$

$\frac{1}{8} - \frac{7}{8 \times 12} + \frac{7 \times 10}{8 \times 12 \times 16} - \ldots =$

Vedclass Test Series

Exam Paper Generator

Online Exam Module