If $\cos \left(\frac{\alpha-\beta}{2}\right)=2 \cos \left(\frac{\alpha+\beta}{2}\right)$,then $\tan \frac{\alpha}{2} \tan \frac{\beta}{2}=$

  • A
    $\frac{1}{2}$
  • B
    $\frac{1}{4}$
  • C
    $\frac{1}{3}$
  • D
    $\frac{1}{8}$

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