If $O$ is the circumcentre and $O'$ is the orthocentre of the triangle $ABC$,then $\overrightarrow{O'A} + \overrightarrow{O'B} + \overrightarrow{O'C} = $

  • A
    $\overrightarrow{OO'}$
  • B
    $2\,\overrightarrow{O'O}$
  • C
    $2\,\overrightarrow{OO'}$
  • D
    $0$

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