If 10 is the mean of the data 2, 3, 5, 18, 17 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given the mean $\bar{x} = 10$ for the $10$ observations: $\frac{2+3+5+18+17+15+13+x+9+7}{10} = 10$ $\Rightarrow 89 + x = 100$ $\Rightarrow x = 11$

Vedclass · Accepted Answer

$4.8$

Vedclass · Answer

(B) Given the mean $\bar{x} = 10$ for the $10$ observations: $\frac{2+3+5+18+17+15+13+x+9+7}{10} = 10$ $\Rightarrow 89 + x = 100$ $\Rightarrow x = 11$ The data set is ${2, 3, 5, 18, 17, 15, 13, 11, 9, 7}$. The mean deviation about the mean is calculated as $\frac{1}{n} \sum |x_i - \bar{x}|$:   $x_i$ $|x_i - 10|$   $2$ $8$   $3$ $7$   $5$ $5$   $18$ $8$   $17$ $7$   $15$ $5$   $13$ $3$   $11$ $1$   $9$ $1$   $7$ $3$   Sum of absolute deviations $= 8+7+5+8+7+5+3+1+1+3 = 48$. Mean Deviation $= \frac{48}{10} = 4.8$.

Marks obtained	$10-20$	$20-30$	$30-40$	$40-50$	$50-60$	$60-70$	$70-80$
No of students	$2$	$3$	$8$	$14$	$8$	$3$	$2$

Class Interval	$0-4$	$4-8$	$8-12$	$12-16$
Frequency	$4$	$3$	$2$	$1$

If $10$ is the mean of the data $2, 3, 5, 18, 17, 15, 13, x, 9, 7$,then the mean deviation of this data about its mean is

Similar Questions

Find the mean deviation about the median for the given data:

$x_i$ $15$ $21$ $27$ $30$ $35$

$f_i$ $3$ $5$ $6$ $7$ $8$

Let the mean of $6$ observations $1, 2, 4, 5, x,$ and $y$ be $5$ and their variance be $10$. Then their mean deviation about the mean is equal to $........$.

The mean of $5$ observations is $5$ and their variance is $124$. If three of the observations are $1, 2$ and $6$,then the mean deviation from the mean of the data is:

Find the mean deviation about the mean for the following data.
Marks obtained $10-20$ $20-30$ $30-40$ $40-50$ $50-60$ $60-70$ $70-80$
No of students $2$ $3$ $8$ $14$ $8$ $3$ $2$

The mean deviation about the mean for the following data is

Class Interval $0-4$ $4-8$ $8-12$ $12-16$

Frequency $4$ $3$ $2$ $1$

Vedclass Test Series

Exam Paper Generator

Online Exam Module