If $p_1, p_2, p_3$ are the altitudes and $a=4, b=5, c=6$ are the sides of a triangle $ABC$,then $\frac{1}{p_1^2} + \frac{1}{p_2^2} + \frac{1}{p_3^2} =$

  • A
    $\frac{77}{225}$
  • B
    $\frac{44}{225}$
  • C
    $\frac{308}{225}$
  • D
    $\frac{22}{75}$

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