If $\frac{x^2+7}{(x^2+1)(x-2)}=\frac{A}{x-2}+\frac{Bx+C}{x^2+1}$, then the determinant of the matrix $\begin{bmatrix} A & B \\ C & \frac{2}{5} \end{bmatrix}$ is

  • A
    $5$
  • B
    $-5$
  • C
    $\frac{94}{25}$
  • D
    $-2$

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