If $\int \frac{\sin^8 x - \cos^8 x}{1 - 2 \sin^2 x \cos^2 x} dx = A \sin 2x + B$, then $A$ is equal to

  • A
    $-\frac{1}{2}$
  • B
    $-1$
  • C
    $\frac{1}{2}$
  • D
    $1$

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