If $|\vec{a}|=4, |\vec{b}|=5, |\vec{a}-\vec{b}|=3$ and $\theta$ is the angle between the vectors $\vec{a}$ and $\vec{b}$, then $\cot^2 \theta=$

  • A
    $\frac{9}{16}$
  • B
    $\frac{4}{3}$
  • C
    $\frac{3}{4}$
  • D
    $\frac{16}{9}$

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