If a and b are two non-zero perpendicular vec | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Given $a \cdot y = c$ and $a 	imes y = b$. Since $a$ and $b$ are perpendicular, $a \cdot b = 0$. Taking the cross product of $a$ with the second

Vedclass · Accepted Answer

$\frac{1}{|a|^2}[c a - (a 	imes b)]$

Vedclass · Answer

(C) Given $a \cdot y = c$ and $a 	imes y = b$. Since $a$ and $b$ are perpendicular, $a \cdot b = 0$. Taking the cross product of $a$ with the second equation: $a 	imes (a 	imes y) = a 	imes b$. Using the vector triple product identity $a 	imes (b 	imes c) = (a \cdot c)b - (a \cdot b)c$: $(a \cdot y)a - (a \cdot a)y = a 	imes b$. Substitute $a \cdot y = c$ and $a \cdot a = |a|^2$: $c a - |a|^2 y = a 	imes b$. Rearranging for $y$: $|a|^2 y = c a - (a 	imes b)$. $y = \frac{1}{|a|^2}[c a - (a 	imes b)]$.

If $a$ and $b$ are two non-zero perpendicular vectors, then a vector $y$ satisfying the equations $a \cdot y = c$ (where $c$ is a scalar) and $a \times y = b$ is

Similar Questions

$A$ particle moves in a circle of radius $25 \ cm$ at two revolutions per second. The acceleration of the particle in $m/s^2$ is

The compound prepared by a substitution reaction of benzene is

One litre of oxygen at a pressure of $1 ~atm$ and two litres of nitrogen at a pressure of $0.5 ~atm$ are introduced into a vessel of volume $1 ~L$. If there is no change in temperature,the final pressure of the mixture of gas (in $atm$) is

$A$ cell of $emf$ $E$ has an internal resistance $r$ and is connected to a rheostat. When the resistance $R$ of the rheostat is changed,which is the correct graph of the potential difference $V$ across it?

The floral formula (image) is that of

Vedclass Test Series

Exam Paper Generator

Online Exam Module