If $X \sim B(6, p)$ is a binomial variate and $\frac{P(X=4)}{P(X=2)}=\frac{1}{9}$, then $p=$

  • A
    $\frac{1}{2}$
  • B
    $\frac{1}{9}$
  • C
    $\frac{1}{3}$
  • D
    $\frac{1}{4}$

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