If varepsilon_0 and mu_0 represent the permit | vedclass

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(A) From Maxwell's relation for electromagnetic waves, the speed of light $c$ is given by the formula: $c = \frac{1}{\sqrt{\mu_0 \varepsilon_0}}$.Squa

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$M^0 L^{-2} T^2$

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(A) From Maxwell's relation for electromagnetic waves, the speed of light $c$ is given by the formula: $c = \frac{1}{\sqrt{\mu_0 \varepsilon_0}}$.Squaring both sides, we get: $c^2 = \frac{1}{\mu_0 \varepsilon_0}$.Therefore, the product $\mu_0 \varepsilon_0 = \frac{1}{c^2}$.The dimensions of the speed of light $c$ are $[LT^{-1}]$.Substituting the dimensions, we get: $[\mu_0 \varepsilon_0] = [LT^{-1}]^{-2}$.Simplifying this, we obtain: $[\mu_0 \varepsilon_0] = [L^{-2} T^2]$.In terms of mass, length, and time, this is written as $[M^0 L^{-2} T^2]$.

If $\varepsilon_0$ and $\mu_0$ represent the permittivity and permeability of free space respectively, then the dimension of the product $\varepsilon_0 \mu_0$ is,

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