If R is the Rydberg constant in cm^{-1}, then | vedclass

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(B) The wavelength $\lambda$ of radiation emitted by a hydrogen atom is given by the Rydberg formula: $\frac{1}{\lambda} = R \left[ \frac{1}{n_f^2} -

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$\frac{7}{5R}$ to $\frac{19}{5R} \ cm$

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(B) The wavelength $\lambda$ of radiation emitted by a hydrogen atom is given by the Rydberg formula: $\frac{1}{\lambda} = R \left[ \frac{1}{n_f^2} - \frac{1}{n_i^2} \right]$.For each spectral series, the range of wavelengths is determined by the transition from $n_i = n_f + 1$ to $n_i = \infty$.$1$. Lyman series $(n_f = 1)$: $\lambda$ ranges from $\frac{1}{R}$ to $\frac{4}{3R}$.$2$. Balmer series $(n_f = 2)$: $\lambda$ ranges from $\frac{4}{R}$ to $\frac{36}{5R}$.$3$. Paschen series $(n_f = 3)$: $\lambda$ ranges from $\frac{9}{R}$ to $\frac{144}{7R}$.Comparing the given options, the range $\frac{7}{5R}$ to $\frac{19}{5R}$ does not correspond to any of the spectral series of the hydrogen atom.

If $R$ is the Rydberg constant in $cm^{-1}$, then the hydrogen atom does not emit any radiation of wavelength in the range of

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