If theta in left(frac{pi}{2}, frac{3 pi}{2}ri | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given expression: $\sqrt{4 \cos^{4} 	heta + \sin^{2} 2 	heta} + 4 \cot 	heta \cos^{2} \left(\frac{\pi}{4} - \frac{	heta}{2}ight)$$= \sqrt{4

Vedclass · Accepted Answer

$2 \cot 	heta$

Vedclass · Answer

(B) Given expression: $\sqrt{4 \cos^{4} 	heta + \sin^{2} 2 	heta} + 4 \cot 	heta \cos^{2} \left(\frac{\pi}{4} - \frac{	heta}{2}ight)$$= \sqrt{4 \cos^{4} 	heta + (2 \sin 	heta \cos 	heta)^{2}} + 2 \cot 	heta \left[2 \cos^{2} \left(\frac{\pi}{4} - \frac{	heta}{2}ight)ight]$$= \sqrt{4 \cos^{4} 	heta + 4 \sin^{2} 	heta \cos^{2} 	heta} + 2 \cot 	heta \left[1 + \cos \left(\frac{\pi}{2} - 	hetaight)ight]$$= \sqrt{4 \cos^{2} 	heta (\cos^{2} 	heta + \sin^{2} 	heta)} + 2 \cot 	heta (1 + \sin 	heta)$$= |2 \cos 	heta| + 2 \cot 	heta + 2 \cot 	heta \sin 	heta$$= |2 \cos 	heta| + 2 \cot 	heta + 2 \cos 	heta$Since $	heta \in \left(\frac{\pi}{2}, \frac{3 \pi}{2}ight)$, $\cos 	heta $= -2 \cos 	heta + 2 \cot 	heta + 2 \cos 	heta$$= 2 \cot 	heta$

If $\theta \in \left(\frac{\pi}{2}, \frac{3 \pi}{2}\right)$, then the value of $\sqrt{4 \cos^{4} \theta + \sin^{2} 2 \theta} + 4 \cot \theta \cos^{2} \left(\frac{\pi}{4} - \frac{\theta}{2}\right)$ is

Similar Questions

If $\sin \theta + \cos \theta = p$ and $\sin^3 \theta + \cos^3 \theta = q$,then $p(p^2 - 3)$ is equal to

$\tan 2 \alpha \cdot \tan \left(30^{\circ}-\alpha\right)+\tan 2 \alpha \cdot \tan \left(60^{\circ}-\alpha\right)+\tan \left(60^{\circ}-\alpha\right) \cdot \tan \left(30^{\circ}-\alpha\right)$ is equal to

The value of $\left(\sin 70^{\circ}\right)\left(\cot 10^{\circ} \cot 70^{\circ}-1\right)$ is

$\sin 20^{\circ}(4+\sec 20^{\circ})=$

If $A = \sin \theta |\sin \theta|$,$B = \cos \theta |\cos \theta|$ and $\frac{99 \pi}{2} \leq \theta \leq \frac{100 \pi}{2}$,then

Vedclass Test Series

Exam Paper Generator

Online Exam Module