જો $x_1 = 3$ અને $x_{n+1} = \sqrt{2 + x_n}$ હોય,તો $\lim_{n \to \infty} x_n$ ની કિંમત શોધો.

$\mathop {\lim }\limits_{x \to 0} \frac{{{{\left( {1 - \cos 2x} \right)}^2}}}{{2x\tan x - x\tan 2x}}$ ની કિંમત શોધો.

$\lim _{x \rightarrow 1} \left( \lim _{y \rightarrow \infty} y \left( (e^x)^{1/y} - 1 \right) \right) = $

જો $0 \leq x \leq \pi / 2$ હોય,તો $\lim _{x \rightarrow a} \frac{|2 \cos x-1|}{2 \cos x-1}$

$\mathop {\lim }\limits_{x \to \pi /2} \frac{\tan 3x}{x} = $

$\lim _{x}$ ${\rightarrow 0} \frac{8}{x^8}\left[1-\cos \left(\frac{x^2}{2}\right)-\cos \left(\frac{x^2}{4}\right)+\cos \left(\frac{x^2}{2}\right) \cdot \cos \left(\frac{x^2}{4}\right)\right]$ ની કિંમત શોધો.