If sim p to q is false and q leftrightarrow r | vedclass

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(C) $1$. The implication $\sim p 	o q$ is false only when $\sim p$ is $T$ and $q$ is $F$.$2$. Since $\sim p = T$, it follows that $p = F$.$3$. Given

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$(F, F, T)$

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(C) $1$. The implication $\sim p 	o q$ is false only when $\sim p$ is $T$ and $q$ is $F$.$2$. Since $\sim p = T$, it follows that $p = F$.$3$. Given $q = F$, the biconditional $q \leftrightarrow r$ is false only when $q$ and $r$ have different truth values.$4$. Since $q = F$, $r$ must be $T$ for $q \leftrightarrow r$ to be false.$5$. Therefore, the truth values are $p = F$, $q = F$, and $r = T$, which is $(F, F, T)$.

If $\sim p \to q$ is false and $q \leftrightarrow r$ is false, then the truth value of $(p, q, r)$ is...

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