If $A = \begin{bmatrix} 3 & 2 & 6 \\ 1 & 1 & 2 \\ 2 & 2 & 5 \end{bmatrix}$ and $B = \begin{bmatrix} 1 \\ 0 \\ 1 \end{bmatrix}$ such that $XA = B^T$ and $A^{-1}Y = B$, then find the value of $XY$.

  • A
    $[-1]$
  • B
    $[1]$
  • C
    $[-2]$
  • D
    $[2]$

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If the multiplicative group consists of $2 \times 2$ matrices of the form $\begin{bmatrix} a & a \\ a & a \end{bmatrix}$,where $a \neq 0$ and $a \in \mathbb{R}$,then the inverse of $\begin{bmatrix} 2 & 2 \\ 2 & 2 \end{bmatrix}$ is:

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