If r.m.s. velocity of a gas is V_{rms} = 1840 | vedclass

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(C) The formula for $r.m.s.$ velocity is given by $V_{rms} = \sqrt{\frac{3P}{\rho}}$.Rearranging the formula to solve for pressure $P$,we get $P = \fr

Vedclass · Accepted Answer

$1.01 	imes 10^5 \ N/m^2$

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(C) The formula for $r.m.s.$ velocity is given by $V_{rms} = \sqrt{\frac{3P}{ho}}$.Rearranging the formula to solve for pressure $P$,we get $P = \frac{ho V_{rms}^2}{3}$.Substituting the given values: $ho = 8.99 	imes 10^{-2} \ kg/m^3$ and $V_{rms} = 1840 \ m/s$.$P = \frac{8.99 	imes 10^{-2} 	imes (1840)^2}{3}$.$P = \frac{8.99 	imes 10^{-2} 	imes 3385600}{3}$.$P = \frac{304365.44}{3} \approx 101455.14 \ N/m^2$.Rounding to the appropriate significant figures,$P \approx 1.01 	imes 10^5 \ N/m^2$.

If $r.m.s.$ velocity of a gas is $V_{rms} = 1840 \ m/s$ and its density $\rho = 8.99 \times 10^{-2} \ kg/m^3$,the pressure of the gas will be

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