If $96500 \ C$ of electricity liberates one gram equivalent of any substance,the time taken for a current of $0.15 \ A$ to deposit $20 \ mg$ of copper from a solution of copper sulphate is (Chemical equivalent of copper = $32$).

  • A
    $5 \ \text{min} \ 20 \ \text{sec}$
  • B
    $6 \ \text{min} \ 42 \ \text{sec}$
  • C
    $4 \ \text{min} \ 40 \ \text{sec}$
  • D
    $5 \ \text{min} \ 50 \ \text{sec}$

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