If $\lambda_{m}$ denotes the wavelength at which the radioactive emission from a black body at a temperature $T \; K$ is maximum,then

Assume that for solar radiation,the surface temperature of the Sun is $6000 \,K$. If Wien's constant '$b$' is $2.897 \times 10^{-3} \,m-K$,the value of the maximum wavelength will be: (in $Å$)

In a certain planetary system,it is observed that one of the celestial bodies having a surface temperature of $200 \; K$,emits radiation of maximum intensity near the wavelength $12 \; \mu m$. The surface temperature (in $K$) of a nearby star which emits light of maximum intensity at a wavelength $\lambda = 4800 \; \mathring A$ is

$A$ body at $3000 \,K$ emits maximum energy at a wavelength of $9660 Å$. If the sun emits maximum energy at a wavelength of $4950 Å$, what would be the temperature of the sun (in $\,K$)?

$A$ black body has a maximum wavelength $\lambda_{m}$ at a temperature of $2000 \ K$. Its corresponding wavelength at a temperature of $3000 \ K$ will be:

The wavelength of the radiation emitted by a black body is $1 \,mm$ and Wien's constant is $3 \times 10^{-3} \,mK$. Then the temperature of the black body will be (in $\,K$)