If $V$ is the accelerating voltage,then the maximum frequency of continuous $X$-rays is given by

  • A
    $\frac{eh}{V}$
  • B
    $\frac{hV}{e}$
  • C
    $\frac{eV}{h}$
  • D
    $\frac{h}{eV}$

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Similar Questions

What does the hardness of $X$-rays obtained from an $X$-ray tube indicate?

The wavelengths of $K_\alpha$ lines of two elements are $250 \, pm$ and $179 \, pm$, respectively. The number of elements between these two elements in the periodic table will be:

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When the accelerating voltage applied to the electrons is increased beyond a critical value in an $X$-ray tube,what happens to the $X$-ray spectrum?

$STATEMENT-1$: If the accelerating potential in an $X$-ray tube is increased, the wavelengths of the characteristic $X$-rays do not change. because
$STATEMENT-2$: When an electron beam strikes the target in an $X$-ray tube, part of the kinetic energy is converted into $X$-ray energy.

The ionization energies of Cobalt $(Co)$,Copper $(Cu)$,and Molybdenum $(Mo)$ are $7.8 \, keV$,$9.0 \, keV$,and $20.1 \, keV$ respectively. If any of these metals are used as a target in an $X$-ray tube operating at $15 \, kV$,then:

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