If $(10)^9 + 2(11)^1(10)^8 + 3(11)^2(10)^7 + \dots + 10(11)^9 = k(10)^9$,then $k$ is equal to:

  • A
    $100$
  • B
    $110$
  • C
    $\frac{121}{10}$
  • D
    $\frac{441}{100}$

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